Epoch Time (Unix Time)
Programming often requires representing the world in programming terms. How do we define 'now' in terms of time? We can define it with a date and time, but that becomes very combersome to handle in code. Fortunately there is a way to represent 'now' as an integer. It's called Unix or Epoch time. It is the number of seconds from January 1, 1970. Seem Arbitrary? Maybe, but it gives us a reference point. It has been ?????????? seconds since the epoch or Jan 1, 1970 (UTC).
Coordinated Universal Time (UTC)
Unix time is based on the time standard: UTC, which stands for Coordinated Universal Time (which can be confusing because its not abbreviated as you might think) but came about due to a compromise between French (TCU) and English (CUT) spellings of the phrase. Vernacular aside, it is simply a way to describe time without timezones. The reference of January 1, 1970 happened several times across the world, depending on location. Hence the use of of UTC time to define Unix time.
Okay so it turns out that Unix Time is not exactly the number of seconds from Jan 1, 1970. It's close, but it does not take into account leap seconds. Since the earth's rotation is slowing it takes a little longer to make a full rotation each year. Its less than a second a year but its worth noting.
var curUnixTime = new Date().getTime(); alert("Number of milliseconds since epoch: " + curUnixTime);
Wait! Technically that is in milliseconds not seconds. To get seconds divide by a thousand and round that bugger so we don't get any decimals points.
var curUnixTime = Math.round(new Date().getTime() / 1000); alert("Number of seconds since epoch: " + curUnixTime);
var curUnixTime:Date = Math.round(new Date().getTime() / 1000); trace("Number of seconds since epoch: " + curUnixTime);
Below is an example of converting a date to Unix time. Enter a date, like your birthday, and find out how many seconds it was since the epoch. If the date (or birthday) was before 1970, the number will be negative.
There are a lot of seconds since 1970, and each day 86400 more go by. Eventually we will not be able to store that number in an integer. In most computer systems today a signed 32-bit integer can represent a number up to 2,147,483,647. With a little math we should be able to figure out when this would happen: If a day has 86400 seconds, an average year would have roughly 86,400 * 365 = 31,536,000 seconds. 2,147,483,647 / 31,536,000 = 68.09625 aka 68.1 years. 68 years from 1970 is 2038, hence the term: Year 2038 Problem.
- Download As3 Example Fla: EpochTimeExample.fla